Optimal. Leaf size=204 \[ -\frac{2 a^7 \left (a+b \sqrt{x}\right )^{p+1}}{b^8 (p+1)}+\frac{14 a^6 \left (a+b \sqrt{x}\right )^{p+2}}{b^8 (p+2)}-\frac{42 a^5 \left (a+b \sqrt{x}\right )^{p+3}}{b^8 (p+3)}+\frac{70 a^4 \left (a+b \sqrt{x}\right )^{p+4}}{b^8 (p+4)}-\frac{70 a^3 \left (a+b \sqrt{x}\right )^{p+5}}{b^8 (p+5)}+\frac{42 a^2 \left (a+b \sqrt{x}\right )^{p+6}}{b^8 (p+6)}-\frac{14 a \left (a+b \sqrt{x}\right )^{p+7}}{b^8 (p+7)}+\frac{2 \left (a+b \sqrt{x}\right )^{p+8}}{b^8 (p+8)} \]
[Out]
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Rubi [A] time = 0.273027, antiderivative size = 204, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133 \[ -\frac{2 a^7 \left (a+b \sqrt{x}\right )^{p+1}}{b^8 (p+1)}+\frac{14 a^6 \left (a+b \sqrt{x}\right )^{p+2}}{b^8 (p+2)}-\frac{42 a^5 \left (a+b \sqrt{x}\right )^{p+3}}{b^8 (p+3)}+\frac{70 a^4 \left (a+b \sqrt{x}\right )^{p+4}}{b^8 (p+4)}-\frac{70 a^3 \left (a+b \sqrt{x}\right )^{p+5}}{b^8 (p+5)}+\frac{42 a^2 \left (a+b \sqrt{x}\right )^{p+6}}{b^8 (p+6)}-\frac{14 a \left (a+b \sqrt{x}\right )^{p+7}}{b^8 (p+7)}+\frac{2 \left (a+b \sqrt{x}\right )^{p+8}}{b^8 (p+8)} \]
Antiderivative was successfully verified.
[In] Int[(a + b*Sqrt[x])^p*x^3,x]
[Out]
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Rubi in Sympy [A] time = 50.0283, size = 184, normalized size = 0.9 \[ - \frac{2 a^{7} \left (a + b \sqrt{x}\right )^{p + 1}}{b^{8} \left (p + 1\right )} + \frac{14 a^{6} \left (a + b \sqrt{x}\right )^{p + 2}}{b^{8} \left (p + 2\right )} - \frac{42 a^{5} \left (a + b \sqrt{x}\right )^{p + 3}}{b^{8} \left (p + 3\right )} + \frac{70 a^{4} \left (a + b \sqrt{x}\right )^{p + 4}}{b^{8} \left (p + 4\right )} - \frac{70 a^{3} \left (a + b \sqrt{x}\right )^{p + 5}}{b^{8} \left (p + 5\right )} + \frac{42 a^{2} \left (a + b \sqrt{x}\right )^{p + 6}}{b^{8} \left (p + 6\right )} - \frac{14 a \left (a + b \sqrt{x}\right )^{p + 7}}{b^{8} \left (p + 7\right )} + \frac{2 \left (a + b \sqrt{x}\right )^{p + 8}}{b^{8} \left (p + 8\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**3*(a+b*x**(1/2))**p,x)
[Out]
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Mathematica [A] time = 0.34184, size = 265, normalized size = 1.3 \[ \frac{2 \left (a+b \sqrt{x}\right )^{p+1} \left (-5040 a^7+5040 a^6 b (p+1) \sqrt{x}-2520 a^5 b^2 \left (p^2+3 p+2\right ) x+840 a^4 b^3 \left (p^3+6 p^2+11 p+6\right ) x^{3/2}-210 a^3 b^4 \left (p^4+10 p^3+35 p^2+50 p+24\right ) x^2+42 a^2 b^5 \left (p^5+15 p^4+85 p^3+225 p^2+274 p+120\right ) x^{5/2}-7 a b^6 \left (p^6+21 p^5+175 p^4+735 p^3+1624 p^2+1764 p+720\right ) x^3+b^7 \left (p^7+28 p^6+322 p^5+1960 p^4+6769 p^3+13132 p^2+13068 p+5040\right ) x^{7/2}\right )}{b^8 (p+1) (p+2) (p+3) (p+4) (p+5) (p+6) (p+7) (p+8)} \]
Antiderivative was successfully verified.
[In] Integrate[(a + b*Sqrt[x])^p*x^3,x]
[Out]
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Maple [F] time = 0.022, size = 0, normalized size = 0. \[ \int{x}^{3} \left ( a+b\sqrt{x} \right ) ^{p}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^3*(a+b*x^(1/2))^p,x)
[Out]
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Maxima [A] time = 1.48508, size = 386, normalized size = 1.89 \[ \frac{2 \,{\left ({\left (p^{7} + 28 \, p^{6} + 322 \, p^{5} + 1960 \, p^{4} + 6769 \, p^{3} + 13132 \, p^{2} + 13068 \, p + 5040\right )} b^{8} x^{4} +{\left (p^{7} + 21 \, p^{6} + 175 \, p^{5} + 735 \, p^{4} + 1624 \, p^{3} + 1764 \, p^{2} + 720 \, p\right )} a b^{7} x^{\frac{7}{2}} - 7 \,{\left (p^{6} + 15 \, p^{5} + 85 \, p^{4} + 225 \, p^{3} + 274 \, p^{2} + 120 \, p\right )} a^{2} b^{6} x^{3} + 42 \,{\left (p^{5} + 10 \, p^{4} + 35 \, p^{3} + 50 \, p^{2} + 24 \, p\right )} a^{3} b^{5} x^{\frac{5}{2}} - 210 \,{\left (p^{4} + 6 \, p^{3} + 11 \, p^{2} + 6 \, p\right )} a^{4} b^{4} x^{2} + 840 \,{\left (p^{3} + 3 \, p^{2} + 2 \, p\right )} a^{5} b^{3} x^{\frac{3}{2}} - 2520 \,{\left (p^{2} + p\right )} a^{6} b^{2} x + 5040 \, a^{7} b p \sqrt{x} - 5040 \, a^{8}\right )}{\left (b \sqrt{x} + a\right )}^{p}}{{\left (p^{8} + 36 \, p^{7} + 546 \, p^{6} + 4536 \, p^{5} + 22449 \, p^{4} + 67284 \, p^{3} + 118124 \, p^{2} + 109584 \, p + 40320\right )} b^{8}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*sqrt(x) + a)^p*x^3,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.328416, size = 618, normalized size = 3.03 \[ -\frac{2 \,{\left (5040 \, a^{8} -{\left (b^{8} p^{7} + 28 \, b^{8} p^{6} + 322 \, b^{8} p^{5} + 1960 \, b^{8} p^{4} + 6769 \, b^{8} p^{3} + 13132 \, b^{8} p^{2} + 13068 \, b^{8} p + 5040 \, b^{8}\right )} x^{4} + 7 \,{\left (a^{2} b^{6} p^{6} + 15 \, a^{2} b^{6} p^{5} + 85 \, a^{2} b^{6} p^{4} + 225 \, a^{2} b^{6} p^{3} + 274 \, a^{2} b^{6} p^{2} + 120 \, a^{2} b^{6} p\right )} x^{3} + 210 \,{\left (a^{4} b^{4} p^{4} + 6 \, a^{4} b^{4} p^{3} + 11 \, a^{4} b^{4} p^{2} + 6 \, a^{4} b^{4} p\right )} x^{2} + 2520 \,{\left (a^{6} b^{2} p^{2} + a^{6} b^{2} p\right )} x -{\left (5040 \, a^{7} b p +{\left (a b^{7} p^{7} + 21 \, a b^{7} p^{6} + 175 \, a b^{7} p^{5} + 735 \, a b^{7} p^{4} + 1624 \, a b^{7} p^{3} + 1764 \, a b^{7} p^{2} + 720 \, a b^{7} p\right )} x^{3} + 42 \,{\left (a^{3} b^{5} p^{5} + 10 \, a^{3} b^{5} p^{4} + 35 \, a^{3} b^{5} p^{3} + 50 \, a^{3} b^{5} p^{2} + 24 \, a^{3} b^{5} p\right )} x^{2} + 840 \,{\left (a^{5} b^{3} p^{3} + 3 \, a^{5} b^{3} p^{2} + 2 \, a^{5} b^{3} p\right )} x\right )} \sqrt{x}\right )}{\left (b \sqrt{x} + a\right )}^{p}}{b^{8} p^{8} + 36 \, b^{8} p^{7} + 546 \, b^{8} p^{6} + 4536 \, b^{8} p^{5} + 22449 \, b^{8} p^{4} + 67284 \, b^{8} p^{3} + 118124 \, b^{8} p^{2} + 109584 \, b^{8} p + 40320 \, b^{8}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*sqrt(x) + a)^p*x^3,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**3*(a+b*x**(1/2))**p,x)
[Out]
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GIAC/XCAS [A] time = 0.267367, size = 1, normalized size = 0. \[ \mathit{Done} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*sqrt(x) + a)^p*x^3,x, algorithm="giac")
[Out]